assign value different position in array

[LucaLuca]

hello .. I reformulated the post with better examples

a =

NaN NaN NaN
NaN NaN NaN
NaN NaN NaN

i want to assign value 0 to last end index position(v)

v is position array

v =

2 1 3
then :

2===> position n. 2 and n.3 =0 (last 2 element =0)
1===> position n. 3=0 (last 1 element =0)
3===> position n.1 and n.2 and n3=0 (last 3 element =0)


the result :

=Nan 0 0
=Nan Nan 0
= 0 0 0

it's possible to do it avoid loop?





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[LucaLuca]

hello .. I reformulated the post with better examples

a =

NaN NaN NaN
NaN NaN NaN
NaN NaN NaN

i want to assign value 0 to last end index position(v)

v is position array

v =

2 1 3 (idx 2..idx 1..idx 3)
then :

2===> position n. 2 and n.3 =0 (last 2 element =0)
1===> position n. 3=0 (last 1 element =0)
3===> position n.1 and n.2 and n3=0 (last 3 element =0)


the result :

=Nan 0 0
=Nan Nan 0
= 0 0 0

it's possible to do it avoid loop?





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Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html

[Andreas Weber]

Post by LucaLuca
i want to assign value 0 to last end index position(v)
v is position array

a = NaN (3);
v = [2 1 3];
a(columns(a):-1:1 <= v.') = 0

a =

NaN 0 0
NaN NaN 0
0 0 0

perhaps someone comes with a better solution....

[LucaLuca]

it looks good..thank you



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