find position originally in new array

[gigiolone123]

i want to find originally index position for a>0

example:

a=
0 1 3
4 0 1
1 2 0

a>0

i want this:

0 1 1
1 0 2
2 3 0

if element=0 i write 0..
if element is >0 i write position of originally array




--
Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html

[Doug Stewart]

Post by gigiolone123
i want to find originally index position for a>0
a=
0 1 3
4 0 1
1 2 0
a>0
0 1 1
1 0 2
2 3 0
if element=0 i write 0..
if element is >0 i write position of originally array
This looks like a homework assignment.

I don't do homework for you. But If you show me what you have done then I
might suggest some changes. :-)

Doug

Post by gigiolone123
--
http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html